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Commit f9e50748 authored by Gröne, Tjark Leon Raphael's avatar Gröne, Tjark Leon Raphael
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Update file Solutions.md

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......@@ -31,9 +31,9 @@ Volumen der Einheitszelle: 59.9 ų
Volumes der einzelnen Ionen (ų):
- $`V_{\rm{Sr}} = \frac{4\pi}{3} (1.44)^{3} = 12,51 `$
- $`V_{\rm{Ti}} = \frac{4\pi}{3} (0.605)^{3} = 0.928`$
- $`V_{\rm{O}} = \frac{4\pi}{3} (1.38)^{3} = 11.01 `$
- $`V_{\rm{Sr}} = \frac{4\pi}{3} (1.44)^{3} = 12,51 `$ ų
- $`V_{\rm{Ti}} = \frac{4\pi}{3} (0.605)^{3} = 0.928`$ ų
- $`V_{\rm{O}} = \frac{4\pi}{3} (1.38)^{3} = 11.01 `$ ų
Volumenanteil:
......@@ -46,9 +46,9 @@ Volumen der Einheitszelle: 528.4 ų
Volumes der einzelnen Ionen (ų):
- $`V_{\rm{Mg}} = \frac{4\pi}{3} (0.57)^{3} = 0.775 `$
- $`V_{\rm{Ti}} = \frac{4\pi}{3} (0.535)^{3} = 0.641`$
- $`V_{\rm{O}} = \frac{4\pi}{3} (1.40)^{3} = 11.50 `$
- $`V_{\rm{Mg}} = \frac{4\pi}{3} (0.57)^{3} = 0.775 `$ ų
- $`V_{\rm{Ti}} = \frac{4\pi}{3} (0.535)^{3} = 0.641`$ ų
- $`V_{\rm{O}} = \frac{4\pi}{3} (1.40)^{3} = 11.50 `$ ų
Volumenanteil:
......
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